i forgot how to resolve equation of the third degree : x³ + x² + x + c

i have look on wikipedia for it and only found the method of cadran but it seems to complicate, I am pretty sure there's a easy way to do this.

or if you got maple at home can you tell me what -x^₃ + 8x² - x +6 =?

come on!!! give a fellow gamer some help

Peut-être que ceci pourra t'aider: http://www.mathforu.com/pdf/equations-troisieme-degre.pdf

Je ne suis pas sûr. Les maths collégiales font exploser ma tête. C'est peut-être la précion sinusidale de ma grippe.

Use Gauss' theorem: If there's a fractional number which is root of a polynomial with integer quotients, then the numerator must divide the independent coefficient (in this case, 6), and the denominator must divide the principal coefficient (in this case, -1). So you gotta try wtih 1, -1, 2, -2, 3, -3, 6 and -6, and see when it equals zero, then divide the polynomial by (x-root)

If you give me sometime I'll solve it

What do you mean by resolve? There is no = sign... do you want to factor it or something?   (maybe it's just been too long from when I had to do this sort of stuff and I am missing the context or something).

thx a lot dog, i hope you get better

Well, the way I showed to you works, but that polyomial you provided has no rational roots, so if you want the results

Order of Polynomial, n = 3

The Coefficients are:
a[0] = -1
a[1] = 8
a[2] = -1
a[3] = 6

The Normalized Coefficients are:
a[0] = 1.00000000000000
a[1] = -8
a[2] = 1
a[3] = -6

The Roots are:

Calculated with http://www.savetman.com/roots.html

yeah i found it thx a lot

the answer i needed was : -(x-6)(x-1)^2